6x^2-2400=0

Solution for 6x^2-2400=0 equation:

6x^2-2400=0

a = 6; b = 0; c = -2400;
Δ = b2-4ac
Δ = 02-4·6·(-2400)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*6}=\frac{-240}{12}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*6}=\frac{240}{12}
=20
$